Re: [xsl] XML Question

Subject: Re: [xsl] XML Question
From: LINKE Markus <markus.linke@xxxxxxxx>
Date: Tue, 3 Oct 2006 16:47:02 -0500 (CDT)
I've tried it but I receive an:

SystemID: xxx.xsl
Location: 98:0
Description: The URI urn:schemas-microsoft-com:xslt does not identify an external Java class

error message at this location:

      </xsl:variable>
      <xsl:value-of select="msxsl:node-set($theResult)"/> <!-- here -->
   </xsl:template>

???

Thanks for your help!
Markus

----- Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote:
> You need to apply this code:
>    http://www.topxml.com/code/default.asp?p=3&id=v20010323001030
> 
> to all leaf nodes in the tree.
> 
> 
> 
> -- 
> Cheers,
> Dimitre Novatchev
> ---------------------------------------
> Truly great madness cannot be achieved without significant
> intelligence.
> ---------------------------------------
> To invent, you need a good imagination and a pile of junk
> -------------------------------------
> You've achieved success in your field when you don't know whether
> what
> you're doing is work or play
> 
> 
> 
> On 10/3/06, LINKE Markus <markus.linke@xxxxxxxx> wrote:
> > this might be the better audience ...
> >
> > ----- LINKE Markus <markus.linke@xxxxxxxx> wrote:
> > > Hi,
> > >
> > > I am not sure if this is the right list for such a question, but
> lets
> > > try :)
> > >
> > > I would like to create a list of xpaths via xsl from a given
> > > xml-structure like this:
> > >
> > > <a>
> > >    <b>
> > >       <c>
> > >          content
> > >       </c>
> > >       <d>
> > >          morecontent
> > >       </d>
> > >    </b>
> > > </a>
> > >
> > > it should show the full xpath like
> > >
> > > a/b/c  ====>   content
> > > a/b/d  ====>   morecontent
> > >
> > > and not just
> > >
> > > c => content
> > > d => morecontent
> > >
> > > Ideas anyone? I am looking for either a script or some xsl ...
> > >
> > > Cheers,
> > > Markus

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