Subject: Re: [xsl] How to find distinct nodes by value? From: "Mukul Gandhi" <gandhi.mukul@xxxxxxxxx> Date: Wed, 11 Oct 2006 23:22:11 +0530 |
<?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/"> <output> <xsl:for-each select="distinct-values(//myElement)"> <myElement><xsl:value-of select="." /></myElement> </xsl:for-each> </output> </xsl:template>
I would like to retrieve only the distinct nodes (by value) from a "//myElement"-like expression; <myElement> is either empty or contains only text.
From this document
<a> <myElement>aaa</myElement> <b> <myElement>aaa</myElement> <myElement>xyz</myElement> <myElement>efg</myElement> </b> <c> <d> <myElement>khl</myElement> <myElement>xyz</myElement> </d> </c> </a>
the result should be (the order doesn't matter)
<myElement>aaa</myElement> <myElement>xyz</myElement> <myElement>efg</myElement> <myElement>khl</myElement>
In early XPath "Working Draft"s there seems to have been a function called "distinct-nodes()" which should have done something similar but it used the identity of the nodes. This document still shows the function http://www.w3.org/TR/2003/WD-xpath-functions-20030502/#func-distinct-nodes and it was removed in http://www.w3.org/TR/2003/WD-xpath-functions-20031112/
A replacement for this function found in http://www.w3.org/TR/2005/WD-xpath-functions-20050404/#func-distinct-nodes-stable
basically tells that
//myElement[empty(subsequence(//myElement, 1, position()-1) intersect .)]
should work to select distinct nodes (by identity).
But I haven't been able to find a solution for distinct nodes by value.
Any suggestions?
-- Regards, Mukul Gandhi
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