Subject: RE: [xsl] how to keep big integer format? From: "Lin, Jessica" <jlin@xxxxxxxxxxx> Date: Fri, 20 Oct 2006 08:57:53 -0700 |
I am using XSLT2.0. Thanks Michael, David, and Brian. Now I have better understanding of number format. --- Jessica -----Original Message----- From: Brian Martinez [mailto:Brian.Martinez@xxxxxxxxxxxx] Sent: Friday, October 20, 2006 8:19 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: [xsl] how to keep big integer format? I knew there was something strange about the original output as I'd never seen a result like that in XSLT 1.0. I guess I should have asked her which version she was using. . . . live and learn, b. > -----Original Message----- > From: Michael Kay [mailto:mike@xxxxxxxxxxxx] > Sent: Thursday, October 19, 2006 5:19 PM > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: RE: [xsl] how to keep big integer format? > > > > > > > > I am using xslt to transform xml to xml and want to update > > object_id value by adding 1. But the result returns > > 4.967039E6 instead of 4967039. > > How can I get what I want? > > > > XSLT 1.0 never uses exponential notation on output; XSLT 2.0 uses it by > default for floating point numbers outside the range 1e-6 to 1e+6. The > simplest way to avoid exponential notation is to use integer arithmetic > rather than floating point arithmetic. You're probably using floating > point > because that's the default for untyped data when you don't have a schema. > You can convert to an integer instead by using, for example > xs:integer(object_id)+1. - or, of course, by doing schema-aware processing > with a schema that describes the type of object_id as xs:integer. > > Michael Kay > http://www.saxonica.com/
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