Subject: RE: [xsl] Get Document File name From: "Philip Vallone" <philip.vallone@xxxxxxxxxxx> Date: Mon, 23 Oct 2006 18:57:12 -0400 |
Thanks everyone for the help. <xsl:value-of select="tokenize(document-uri(/), '/')[last()]"/> returns the full path. As a fix, I added a required attribute to a top element for Filename. I am not sure if this is the best way about it. Regards, Phil V -----Original Message----- From: Michael Kay [mailto:mike@xxxxxxxxxxxx] Sent: Monday, October 23, 2006 3:58 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: [xsl] Get Document File name > i'm using > > tokenize(document-uri(/), '/')[last()] > > or '\' if working with backslashes. > The document-uri() function returns a URI, not a filename, and URIs always use forwards slashes as separators. Michael Kay http://www.saxonica.com/
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