Re: [xsl] i18n and l10n question

Hi,

I'm still having some problems putting this to use in our case, but I
thank you
already because I've learned some new ways of doing things from this, (As you
might have guessed: these are my first steps in XSL).

I tried to adjust your tip to what we already had, but it didn't seem to
work.
It gave no errors (after I closed some brackets and typed some extra commas
;)), but it just printed the default text several times.

I will give a more concrete example on how I changed your file.

First of all, this is my example source file, named TuranGraphFactory.xml:

<factory>
 <i18n>
    <properties>
        <entry key="factory.name">Turan Graph</entry>
    </properties>
    <node name="nl">
      <properties>
          <entry key="factory.name">Turan Graaf</entry>
      </properties>
    </node>
 </i18n>
</factory>

I made this xslt-file that should transform the TuranGraphFactory.xml
file to a
html-file:

<xsl:transform version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

   <xsl:param name="locale"/>
   <xsl:variable name="locale2" select="substring-before($locale,'_')"/>
   <xsl:key name="l" match="entry" use="concat(../@name,' ',@key)"/>

   <xsl:template match="factory">
       <html>
           <body>
               <h1>
                   <xsl:variable name="key" select="'factory.name'"/>
                   <xsl:for-each select="//entry">
                   <xsl:choose>
                       <xsl:when test="key('l',concat($locale,' ',$key))">
                           <xsl:apply-templates
select="key('l',concat($locale,' ',$key))"/>
                       </xsl:when>
                       <xsl:when test="key('l',concat($locale2,' ',$key))">
                           <xsl:apply-templates
select="key('l',concat($locale2,' ',$key))"/>
                       </xsl:when>
                       <xsl:otherwise>
                           <xsl:apply-templates select="key('l',concat('
',$key))"/>
                       </xsl:otherwise>
                   </xsl:choose>
                   </xsl:for-each>
               </h1>
           </body>
       </html>
   </xsl:template>
</xsl:transform>

The desired result would be a simple html-file that contained one title
with the
name of the graph in the current locale. However I get a file that
contains one
title that is the name of the graph four times: first the english, then the
dutch, then the english and again the dutch.

Any help would really be appreciated.

Nico van Cleemput

Quoting David Carlisle <davidc@xxxxxxxxx>:


if the file you posted is in locale.xml and you have an input element
something like
<ref key="id1"/>
which is supposed to produce this text, then something like

<xsl:stylesheet...
<xsl:param name="locale"/>
<xsl:variable  name="locale2" select="substring-before($locale,'-')"/>
<xsl:key name="l" match="entry" use="concat(../@name,' ',@key)"/>

<xsl:template match="ref">
<xsl:variable name="key" select="@key"/>
<xsl:for-each select="document('locale.xml')">
 <xsl:choose>
  <xsl:when test="key('l',concat($locale,' '$key)">
     <xsl:apply-templates select="key('l',concat($locale,' ',$key)"/>
  </xsl:when>
  <xsl:when test="key('l',concat($locale2,' '$key)">
     <xsl:apply-templates select="key('l',concat($locale2,' ',$key)"/>
  </xsl:when>
  <xsl:otherwise>
     <xsl:apply-templates select="key('l',concat(' ',$key)"/>
  </xsl:otherwise>
  </xsl:choose>

which (if I typed it in right) would mean that setting the external
local parameter to "en-uk"  would mean it would try in order, en-uk, en,
and the defualt.

David

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