Re: [xsl] Filter leading numbers out of Strings

[Rolf Leopold <leopoldmail@xxxxxx>]

Hi Michael,

thank`s a lot for your help.
After your advice i realised that i only meant the leading numbers of 
any other characters without the trailing numbers.
Anyhow, here ist my solution based on your hint:
<xsl:variable name="stringJunK" 
select="translate($String,'0123456789','')"/>(filter out all numbers)
<xsl:variable name="firstCharacterOfJunK" 
select="substring($stringJunK,1,1)"/>(Get the first character of the 
non-numbers)
<xsl:variable name="leadingNumbers" 
select="substring-before($String,$firstCharacterOfJunK)"/>(get the 
numbers before the first non-number sign)
(Exception:Only numbers, where i use an additional if-query).

Cheers,
Rolf

Michael Kay schrieb:
> You say leading numbers, but you don't give an example with a trailing
> number. What do you want to happen to 123ABC789?
>
> Also, the non-numeric parts of your strings contain A-Z only. Is that a
> feature of the data, or just an accident of your examples?
>
> You can handle your examples with translate($in, 'ABCDE...Z', '').
>
> Michael Kay
> http://www.saxonica.com/
>
>   
> > -----Original Message-----
> > From: leopoldmail@xxxxxx [mailto:leopoldmail@xxxxxx] 
> > Sent: 06 November 2006 07:01
> > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> > Subject: [xsl] Filter leading numbers out of Strings
> >
> > Hi,
> >
> > i have stings in different length with leading numbers  in an 
> > XML-File which i want to transform into another XML-File:
> > Is it possible to only filter out leading numbers of the 
> > strings without using a recursive template and without using xsl2.0?
> > For example:
> > "1234AB" should be "1234"
> > "123456ABC" should be "123456"
> > "123456789A" should be "123456789"
> >
> > thank`s a lot for any help,
> > Rolf