Subject: Re: [xsl] combination of copy-of and apply-templates From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 22 Nov 2006 12:34:04 GMT |
> This does exactly what I want except for one thing: it also copies > the myhtml tag. What am I doing wrong? Or rather it copies the myhtml element (xslt never processes tags) You have an xsl:cop, un that template, simply remove it. <xsl:template match="myhtml"> <xsl:copy> <xsl:apply-templates select="child::node()"/> </xsl:copy> </xsl:template> should be <xsl:template match="myhtml"> <xsl:apply-templates select="child::node()"/> </xsl:template> <xsl:template match="myhtml"> <xsl:apply-templates/> </xsl:template> as child::node()" is the default for apply templates. Also <xsl:template match="//mytag"> can be written as <xsl:template match="mytag"> as you never need to start a match pattern with // (it has no effect on which nodes are matched, only on te hdefault priority) David
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