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Subject: Re: [xsl] combination of copy-of and apply-templates From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 22 Nov 2006 12:34:04 GMT |
> This does exactly what I want except for one thing: it also copies
> the myhtml tag. What am I doing wrong?
Or rather it copies the myhtml element (xslt never processes tags)
You have an xsl:cop, un that template, simply remove it.
<xsl:template match="myhtml">
<xsl:copy>
<xsl:apply-templates select="child::node()"/>
</xsl:copy>
</xsl:template>
should be
<xsl:template match="myhtml">
<xsl:apply-templates select="child::node()"/>
</xsl:template>
<xsl:template match="myhtml">
<xsl:apply-templates/>
</xsl:template>
as child::node()" is the default for apply templates.
Also <xsl:template match="//mytag">
can be written as
<xsl:template match="mytag">
as you never need to start a match pattern with // (it has no effect on
which nodes are matched, only on te hdefault priority)
David
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