[xsl] xpath if expression in Java

[James Neff <jneff@xxxxxxxxxxxxxxxx>]

Greetings,

My apologies if this is not the correct list to post this question on.  
I did look for an Xpath list specific to Java but could not find one.
I have the following method in my Java application:

public String evaluateDocument(String inputDoc, String xPathExpression){

      String results = "";
              try{
          XPathFactory factory = XPathFactory.newInstance();
          XPath xPath = factory.newXPath();
          InputSource inputSource = new InputSource(new 
StringReader(inputDoc));
          results = (String) xPath.evaluate(xPathExpression, 
inputSource, XPathConstants.STRING);                      }
        catch(Exception  e){
          System.out.println("XpathHelper.evaluateDocument, 
xPathExpression: " + xPathExpression + "  exception: " + e);          }
                return results;
          }


The inputDoc is:

<enrollment_record>
  <member_identifier>1234567890</member_identifier>
  <subscriber_number>1234567890</subscriber_number>
</enrollment_record>


The XPath expression is:

if (enrollment_record/subscriber_number = 
enrollment_record/member_identifier) then '1' else '2'


If I run this XPath Expression from an XSLT stylesheet from the command 
line within a <xsl:value-of> element, I get the correct result.


However, from within my java applicaiton I get:
exception: javax.xml.xpath.XPathExpressionException


It does not like the "if" statement within the XPath.  Other simple 
XPath expressions do work.  It's as if the Java application is using an 
older parser that doesn't recognize the "if" statement.

How can I get my Java application to correctly process this XPath 
expression?

Can someone point me in the right direction, or at least tell me which 
mailing list to post my question to?

Thank you in advance,
James