Subject: [xsl] Separate same level elements on a criteria From: "Spencer Tickner" <spencertickner@xxxxxxxxx> Date: Fri, 19 Jan 2007 12:30:57 -0800 |
I'm wondering if anyone has a slick way of solving this problem. I have an xml document like:
<root> <head_document>Title</head_document> <para>This is a paragraph</para> <bold_para>This is a paragraph</bold_para> <head>TOC</head> <section>1. Title</section> <section>2. Title</section> <head>Heading 1</head> <paragraph_indent>This is a paragraph</paragraph_indent> <paragraph_outdent>This is a paragraph</paragraph_outdent> <head>Heading 2</head> <paragraph>This is a paragraph</paragraph> <chart>This is a chart</chart> </root>
Basically I'm making a bunch of html documents from this xml document and a table of contents. Table of contents is easy (I need to grab the <head_document> element and skip the <head>TOC</head> element):
<xsl:template match="root" mode="toc"> <ul> <xsl:for-each select="head_document|head[not(contains(., 'TOC'))]"> <li>Do Something</li> </xsl:for-each> </ul> </xsl:template>
Ok, so that all works great, I now have to do something similar to above but apply-templates to all the elements that belong with the heads I want. ie: <head_document> down to <head>, skip <head>TOC</head>, next <head> element down to the next <head> element, repeat.
Any ideas on how to do this would be very helpful. I thought group-by would probably be the answer but so far my research hasn't turned up anything.
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