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Subject: Re: [xsl] testing for position of an element and displaying it accordingly From: xslt.new <xslt.new@xxxxxxxxx> Date: Mon, 22 Jan 2007 14:49:02 -0600 |
That was only a typo here. Do you have any other ideas or suggestions ? please let em knwo
For one, your <fo:inline> elements are not closed in the bottom 3 template rules.
ms wrote: > Hello: > > I have tried to implement this solution but I dont > know where I am going wrong. Here is my complete code: > > This template is used for formatting. > <xsl:template name="lists"> > <xsl:param name="format"/> > <fo:list-block> > <fo:list-item> > <fo:list-item-label> > <xsl:choose> > <xsl:when test="$format = '1'"> > <fo:block> > <fo:inline> > <xsl:number format="1"/>.</fo:inline> > </fo:block> > </xsl:when> > </xsl:choose> > </fo:list-item-label> > <fo:list-item-body start-indent="body-start()" > end-indent="0pt"> > <fo:block> > <xsl:apply-templates> > > </xsl:apply-templates> > </fo:block> > </fo:list-item-body> > </fo:list-item> > </fo:list-block> > </xsl:template> > > > This template calls the above template for formatting: > > <xsl:template match="r1"> > <xsl:if test="child::a"> > <xsl:apply-templates select="a" mode="t"/> > </xsl:if> > > <xsl:call-template name="lists"> > <xsl:with-param > name="format">1</xsl:with-param> > </xsl:call-template> > </xsl:template> > > This is the template for element a which is a child of > <r1>. > > <xsl:template match="a" mode="t"> > <fo:block space-before="6pt"> > <fo:inline><xsl:value-of select="."/> > </fo:block> > </xsl:template> > > <xsl:template match="a"> > <fo:block space-before="6pt"> > <fo:inline><xsl:value-of select="."/> > </fo:block> > </xsl:template> > > <xsl:template match="text"> > <fo:block space-before="6pt"> > <fo:inline><xsl:apply-templates/> > </fo:block> > </xsl:template> > > > And my Input is: > <r1> > <a>test</a> > <a>test2</a> > <text>test test</text> > <a>test3</a> > </r1> > > My desired output is: > > test > test2 > 1. test test > test3 > > > The reason for checking if <a> is a child of <r1> and > applying the mode is so that this <a> appears above > <r1> without getting formatted as 1. test > > So even though <r1> element is formatted to be 1., any > <a> element which appear immediately after <r1> should > not be formatted. If there is an <a> element after > some other element like in this example <text>, then > it should be displayed as it is in the document tree. > > Please let me know if this is clear and if there is a > way to do it and if there is amistake in my code. > > --- ms <mina_hurray@xxxxxxxxx> wrote: > >> Hello: >> >> I did see the axis specifier thread on this list, >> unfortunately it is not me, but I am facing a >> similar >> issue. I tried to implement the solutions given in >> those, but I was not successful and thats te reason >> for posting this issue. >> >> >> --- Michael Kay <mike@xxxxxxxxxxxx> wrote: >> >>> I assume you're the same person as xslt.new who >>> posted "axis specifiers" >>> last week (if not, it's a remarkable that you have >>> exactly the same problem >>> and the same misunderstandings). >>> >>> We need to go back a step. You haven't understood >> a >>> word of the explanations >>> we gave you last week. Giving you the same >>> explanations again isn't going to >>> do much good. I'm really trying hard to read your >>> postings and work out >>> which step in the learning process you've got >> stuck >>> on, but I'm struggling. >>> >>> The normal way of processing an XML document is to >>> work top-down. First, you >>> have to think of the document as a tree, with the >>> root at the top (strange >>> in botany, but not in computing). The document >> node >>> itself is at the top, >>> then the r1 element, and (a,a,b,a) are below the >> r1 >>> element, at the next >>> level down (I stress this because you talk of >> test3 >>> as being "below" b, >>> which means you're not yet thinking in tree >> terms). >>> So top down processing >>> means you write a template rule for r1, which >>> typically applies templates to >>> each of its children. You then define template >> rules >>> for each kind of child. >>> >>> This works when the rules for an element are >>> independent of where it appears >>> relative to other elements at the same level. For >>> example, if every a >>> element is processed by converting the <a> tag to >> a >>> <p>, then you can write >>> a template rule >>> >>> <xsl:template match="a"> >>> <p><xsl:apply-templates/></p> >>> </xsl:template> >>> >>> Similarly, if every b is processed by outputting a >>> <p> but with a sequence >>> number attached, you can write >>> >>> <xsl:template match="b"> >>> <p><xsl:number/>: <xsl:apply-templates/></p> >>> </xsl:template> >>> >>> Now, your input and your processing seems to >> follow >>> this conventional style. >>> As far as we can see, you've got a perfectly >>> straightforward easy >>> transformation to do here that yields to the basic >>> techniques in chapter 1 >>> of any textbook, and we can't see why you're >> making >>> it so difficult. >>> >>> Michael Kay >>> http://www.saxonica.com/ >>> >>> >>> >>>> -----Original Message----- >>>> From: ms [mailto:mina_hurray@xxxxxxxxx] >>>> Sent: 19 January 2007 14:58 >>>> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx >>>> Subject: [xsl] testing for position of an >> element >>> and >>>> displaying it accordingly >>>> >>>> Hi all: >>>> >>>> My input XML looks like this; >>>> >>>> <r1> >>>> <a>test</a> >>>> <a>test2</a> >>>> <b>test test</b> >>>> <a>test3</a> >>>> </r1> >>>> >>>> For this XML, I would like to write an XSLT >> which >>> basically >>>> achieves the following: >>>> >>>> 1) For the <a> elements which are above the <b> >>> element, they >>>> should be displayed this way: >>>> >>>> Test >>>> Test2 >>>> 1)test test >>>> >>>> 2) For the <a> element which appears after the >> <b> >>> element, I >>>> want it displayed after the <b> element: >>>> >>>> Test >>>> Test2 >>>> 1)test test >>>> test3 >>>> >>>> How can I achieve this in XSLT? I tried testing >>> the >>>> position, using position()=1. This works >> obviously >>> for the >>>> first <a> element and fails for the second one. >>>> >>>> Please let me know if this is possible? >>>> >>>> >>>> >>>> > ______________________________________________________________ >>>> ______________________ >>>> Do you Yahoo!? >>>> Everyone is raving about the all-new Yahoo! Mail >>> beta. >>>> http://new.mail.yahoo.com >>> >>> >> >> >> >> > ____________________________________________________________________________________ >> Need a quick answer? Get one in minutes from people >> who know. >> Ask your question on www.Answers.yahoo.com >> >> > > > > > ____________________________________________________________________________________ > Yahoo! Music Unlimited > Access over 1 million songs. > http://music.yahoo.com/unlimited
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