Subject: Re: [xsl] Duplicate Nodes in XSL and transform them From: David Carlisle <davidc@xxxxxxxxx> Date: Tue, 30 Jan 2007 17:50:59 GMT |
something like this, assuming 3 iterations. <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output indent="yes"/> <xsl:template match="element/*"> <xsl:variable name="n" select="name()"/> <xsl:for-each select="(//node())[position()<4]"> <xsl:element name="{$n}"> <value> <xsl:text>replaced</xsl:text> <xsl:value-of select="position()"/> </value> </xsl:element> </xsl:for-each> </xsl:template> <xsl:template match="element"> <xsl:copy> <xsl:apply-templates select="*"/> </xsl:copy> </xsl:template> </xsl:stylesheet> $ saxon repl.xml repl.xsl <?xml version="1.0" encoding="utf-8"?> <element> <innerElement> <value>replaced1</value> </innerElement> <innerElement> <value>replaced2</value> </innerElement> <innerElement> <value>replaced3</value> </innerElement> </element>
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] Duplicate Nodes in XSL and tr, Punnoose, Roshan | Thread | RE: [xsl] Duplicate Nodes in XSL an, Michael Kay |
[xsl] Duplicate Nodes in XSL and tr, Punnoose, Roshan | Date | RE: [xsl] Duplicate Nodes in XSL an, Michael Kay |
Month |