Re: [xsl] Newbie question on XSL transformations: multiple sorts on element attributes

[Rob Newman <rlnewman@xxxxxxxx>]

Abel and others,

Thanks so much for the prompt response and help! I really appreciate it.
You are correct that my syntax was incorrect. Unfortunately the  
solution you gave me also seg faults.
The XSLT processor I am using is xsltproc (from the command line). It  
does not give me any useful error output aside from "Segmentation  
fault'. Would you recommend using a different processor?

{hostname} 273%> xsltproc -v -o output.xml transform.xsl input.xml
creating dictionary for stylesheet
reusing dictionary from transform.xsl for stylesheet
Added namespace: xsl mapped to http://www.w3.org/1999/XSL/Transform
Segmentation fault
{hostname} 274%>

> > -- START SNIPPET --
> > <xsl:template match="dataloggerlist">
> >     <xsl:element name="dataloggerlist">
> >         <xsl:apply-templates select="datalogger">
> >             <xsl:sort select="param/@id{dlt}" data-type="number"  
> > order="descending" />
> >             <xsl:sort select="@name" order="ascending" />
> >         </xsl:apply-templates>
> >     </xsl:element>
> > </xsl:template>
> > -- END SNIPPET --
> > (Note: the datalogger template outputs the data same as before)
>
> This is very strange, as it cannot possibly run, you have a syntax  
> error in your select clause (if you did manage to get it running,  
> can you follow-up with the processor you are using?). The following  
> is in error:
>
> <xsl:sort select="param/@id{dlt}" data-type="number"  
> order="descending" />
>
> Change it to:
>
> <xsl:sort select="param[@id = 'dlt']"  />
>
> and all elements with @id = 'dlt' (i.e., attribute nodes containing  
> the exact match to the text 'dlt') will be output firstly.

Here is the relevant part of the file (changed as per your instruction):

-- START SNIPPET --
<xsl:template match="dataloggerlist">
	<xsl:element name="dataloggerlist">
		<xsl:apply-templates select="datalogger">
			<xsl:sort select="param[@id = 'dlt']" />
		</xsl:apply-templates>
	</xsl:element>
</xsl:template>
-- END SNIPPET --

> >  I would prefer to do this whole process in one step, and avoid  
> > having two XSL files that create an interim XML file that just  
> > gets transformed again.
>
> and you are right, you won't need to.

Can you please give me an example of how to do this in one file? As I  
see it, I have to get the XML structure tight with my first  
transformation before I can apply the sorting rules. In the meantime  
I will keep tinkering.....

Thanks again,
- Rob