Subject: Re: [xsl] not copying duplicate node to the output (remove duplicate node) From: "Mukul Gandhi" <gandhi.mukul@xxxxxxxxx> Date: Fri, 2 Mar 2007 21:44:09 +0530 |
<xsl:template match="node() | @*"> <xsl:copy> <xsl:apply-templates select="node() | @*" /> </xsl:copy> </xsl:template>
<xsl:template match="release[@display_on = 'headlines;'][doc_number = ../release[not(@display_on = 'headlines;')]/doc_number]" />
<xsl:template match="release[@display_on = 'headlines;'][normalize-space(doc_number) = '']"> <xsl:copy-of select="." /> </xsl:template>
<xsl:template match="@display_on[not(. = 'headlines;')]"> <xsl:attribute name="display_on"> <xsl:value-of select="concat(., ';headlines')" /> </xsl:attribute> </xsl:template>
Hi I have this problem: I need to combine two data groups below: A. conditions: 1. Each release has a unique Id. 2. The two groups have duplicated <doc_number>s. if one <release> in data group A has a <doc_number> that is already in data group B, remove that entire <release> node in data group A. 3. Certain <release> does not even have a <doc_number>, but there is a <doc_number /> tag to represent an empty value. in this case, we keep the entire <release> node. 4. insert ";headlines;" into the "display_on" attribute to the <release>. Current file: <!-- start of file --> <releases> <!-- Data group A --> <release id="2" name="AB" display_on="headlines;" type="NEWS"> <doc_number>6</doc_number> </release> <release id="4" name="CD" display_on="headlines;" type="NOTICE"> <doc_number>5</doc_number> </release> <release id="6" name="EF" display_on="headlines;" type="ORDER"> <doc_number>4</doc_number> </release> <release id="8" name="GH" display_on="headlines;" type="ORDER"> <doc_number>3</doc_number> </release> <release id="10" name="IJ" display_on="headlines;" type="NOTICE"> <doc_number>2</doc_number> </release> <release id="12" name="KL" display_on="headlines;" type="NOTICE"> <doc_number /> </release>
<!-- Data group B --> <release id="14" name="XY" display_on="homepage" type="MEMORANDUM"> <doc_number>5</doc_number> </release> <release id="16" name="MN" display_on="sidepage" type="NOTICE"> <doc_number>4</doc_number> </release> <release id="18" name="OP" display_on="otherpage" type="NOTICE"> <doc_number>3</doc_number> </release> </releases> <!-- end of file --> Desired resulting file: <!-- start of file --> <releases> <!-- Data group A --> <release id="2" name="AB" display_on="headlines;" type="NEWS"> <doc_number>6</doc_number> </release> <release id="10" name="IJ" display_on="headlines;" type="NOTICE"> <doc_number>2</doc_number> </release> <release id="12" name="KL" display_on="headlines;" type="NOTICE"> <doc_number /> </release>
<!-- Data group B --> <release id="14" name="XY" display_on="homepage;headlines" type="MEMORANDUM"> <doc_number>5</doc_number> </release> <release id="16" name="MN" display_on="sidepage;headlines" type="NOTICE"> <doc_number>4</doc_number> </release> <release id="18" name="OP" display_on="otherpage;headlines" type="NOTICE"> <doc_number>3</doc_number> </release> </releases> <!-- end of file --> Right now I have this code written to generate the result, but it only works partially. 1. It removes the duplicated <doc_number> from each release, but it does not remove the whole release. 2. It does not insert ";headlines;" into the "display_on" attribute to the <release> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" omit-xml-declaration="yes"/> <xsl:template match="doc_number"> <xsl:if test="not(string(.))">
</xsl:if> <xsl:if test="not(. = following::fcc_doc_number)"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:if> </xsl:template> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> </xsl:stylesheet> Please anyone help out? thank you!
-- Regards, Mukul Gandhi
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