Re: [xsl] how to make all xsl:value-of outputs bold

[Abel Braaksma <abel.online@xxxxxxxxx>]

nick humphrey wrote:
> hi, i've been googling a lot and am relatively still an xsl newbie. i
> was wondering how to make all the xsl:value-of outputs in my xslt to
> output in bold, with only using like one line at the top of the xslt
> file. is that possible? as opposed to wrapping all of them in span
> tags...

With XSLT it is the other way around. You don't change the way 
xsl:value-of works, but you create rules that react on input nodes that, 
when encountered, can do whatever you want. I.e.:

<xsl:template match="Via">
  <fo:block style="font-weight:bold">
     <xsl:value-of select="." />
  </fo:block>
</xsl:template>

Now, depending on how you define your apply-templates, every "Via" node 
will become bold.

If, however, all you are after is creating every fo:block that is in 
your current stylesheet to become bold, I think you are better of 
setting the outermost element to have a style that includes bold. Then, 
your XSL-FO processor will take care of the rest.

I wonder where you get the idea that "only using like one line at the 
top of the xslt file" could change your output. That is not the way XSLT 
works. One-liners are something more common in Perl and are very 
powerful, but don't look for them in XSLT (but you can place your whole 
XSLT in one line, if that's what you're after).

Cheers,
-- Abel Braaksma
  http://www.nuntia.nl