Subject: [xsl] how to sort a union using number()? From: Andrew S Halper <ashalper@xxxxxxxx> Date: Thu, 15 Mar 2007 16:43:43 -0700 |
Greetings, I was wondering if someone might explain how to sort a union of nodes using the number() function. I encountered a point where I needed to apply templates to a union of nodes, sorting them on a common element. The naive approach was (XPaths radically simplified for brevity): <xsl:apply-templates select="Classifier.feature/Attribute|$associations"> <xsl:sort select="number(NumberString|$associations/NumberString)"/> </xsl:apply-templates> but this resulted in: Error on line 228 of file:/e:/schema.xsl: XPTY0004: A sequence of more than one item is not allowed as the first argument of number() I'm using Saxon 8.9J. Thank you very much, Andy Halper
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