Re: [xsl] Namespace'd XPath expression in Java

["Jacek Radajewski" <jacekrad@xxxxxxxxx>]

See below.
J.
> Here is my Java code:
> ______________________________
> // load XSD
> DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
dbf.setNamespaceAware(true); <----------------------
> DocumentBuilder docBuilder = dbf.newDocumentBuilder();
> Document xsdDoc = docBuilder.parse("path to my xsd");
>
> // eval XPath
> XPath xpath = XPathFactory.newInstance().newXPath();
> xpath.setNamespaceContext(new MyNamespaceContext());
> System.out.println(xpath.evaluate("count(//xs:element)",
> xsdDoc.getDocumentElement()));
> ______________________________
>
> And finally implementation of NamespaceContext:
>
> ______________________________
> public class MyNamespaceContext implements NamespaceContext {
>         public String getNamespaceURI(String prefix) {
>                 if ("xs".equals(prefix)) {
>                         return "http://www.w3.org/2001/XMLSchema";;
>                 } else if ("msdata".equals(prefix)) {
>                         return "urn:schemas-microsoft-com:xml-msdata";
>                 }
>
>                 return XMLConstants.NULL_NS_URI;
>         }
>
>         public String getPrefix(String namespaceURI) {
>                 if ("http://www.w3.org/2001/XMLSchema".equals(namespaceURI)) {
>                         return "xs";
>                 } else if ("urn:schemas-microsoft-com:xml-msdata".equals(namespaceURI)) {
>                         return "msdata";
>                 }
>
>                 return XMLConstants.DEFAULT_NS_PREFIX;
>         }
>
>         public Iterator<String> getPrefixes(String namespaceURI) {
>                 List<String> uris = new ArrayList<String>();
>                 uris.add(getPrefix(namespaceURI));
>                 return uris.iterator();
>         }
> }
> ______________________________
>
> Thanks in advance.


--
Jacek Radajewski