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Re: [xsl] Xsl:param from PHP to html

Subject: Re: [xsl] Xsl:param from PHP to html
From: Steve <subsume@xxxxxxxxx>
Date: Fri, 13 Apr 2007 11:10:26 -0400
Seems like a PHP issue to me...

Have you had success passing other variables from script -> stylesheet?

-S

On 4/13/07, Alan Hale <alan.hale@xxxxxxxxxxx> wrote: 
I know I am doing something fundamentally wrong here, but I cannot
understand what.

I am trying to pass a parameter to a stylesheet from PHP, and use it to
determine the sort order. I am sure the parameter is being assigned
correctly in the PHP code, but when I run the xsl below, I always get
the default value of $SORTBY.

Many thanks

Alan

<html
        xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
        xsl:version='1.0'>

          <!--Define parameter name and set default value-->
      <xsl:param name = "SORTBY">species_name</xsl:param>


<body>


<xsl:for-each select="/fieldguide/account">

<xsl:sort select = "$SORTBY" order = "ascending"/>


         <td align = "center"><xsl:value-of select="species_name"/></td>
        <td width = "40" align = "center"><xsl:value-of
select="has_text"/></td>
        <td width = "40" align = "center"><xsl:value-of
select="has_photo"/></td>
        <td width = "40" align = "center"><xsl:value-of
select="has_drawing"/></td>
        <td width = "40" align = "center"><xsl:value-of
select="has_map"/></td>
        <td align = "right"><xsl:value-of select="format_date"/></td>

      </tr>
      </xsl:for-each>
    </table>
  </body>
</html>

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