Subject: Re: [xsl] eliminating duplicates From: George Cristian Bina <george@xxxxxxxxxxxxx> Date: Fri, 11 May 2007 06:36:27 +0300 |
<xsl:copy-of select=" for $i in distinct-values(*/concat(@dependency, @source, @target)) return *[$i=concat(@dependency, @source, @target)][1]"/>
<xsl:key name="e" match="edge" use="concat(@dependency, @source, @target)"/>
Best Regards, George --------------------------------------------------------------------- George Cristian Bina <oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger http://www.oxygenxml.com
Something like this:
<xsl:for-each-group select="$input/edge" group-by="concat(@source, '-', @target, '-', @dependency)">
<xsl:copy-of select="." />
</xsl:for-each-group>
where $input is contains your 'edge' nodes?
cheers, -- Abel
Garvin Riensche wrote:Hello,
I am wondering what's the best way of getting rid of duplicate nodes which contain more than one attribute. Suppose I have den following xml:
<edge source="IGetter" target="CGetter" dependency="positive"/> <edge source="IGetter" target="CGetter" dependency="positive"/> <edge source="IGetter" target="CCount" dependency="positive"/> <edge source="ICount" target="IGetter" dependency="positive"/> <edge source="ICount" target="CGetter" dependency="positive"/> <edge source="ICount" target="ICount" dependency="positive"/> <edge source="ICount" target="CCount" dependency="positive"/> <edge source="ICount" target="CCount" dependency="positive"/>
How do I get rid of one <edge source="IGetter" target="CGetter" dependency="positive"/> and one <edge source="ICount" target="CCount" dependency="positive"/> which appear twice?
If there was only one attribute, lets say "source" it would be simple:
<xsl:for-each select="//edge[not(./@source=preceding-sibling::edge/@source)]">
<xsl:copy-of select="."/>
</xsl:for-each>
So I thought with more attributes this would work:
<xsl:for-each select="//edge[not(./@source=preceding-sibling::edge/@source
and ./@target=preceding-sibling::edge/@target
and ./@dependency=preceding-sibling::edge/@dependency
)]">
</xsl:for-each>
But of course it doesen't because in one iterartion the "preceding-siblings" doesn't point to the same element.
So, any help would be appreciated on how to get rid of duplicates.
Regards, Garvin
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