Subject: RE: [xsl] Finding the path to a node From: cknell@xxxxxxxxxx Date: Fri, 11 May 2007 09:27:41 -0400 |
<xsl:template match="/"> <xsl:apply-templates select="pages//page[@id='4']" /> </xsl:template> <xsl:template match="page"> <xsl:value-of select="ancestor::page[position() = last()]/@id" /> </xsl:template> -- Charles Knell cknell@xxxxxxxxxx - email -----Original Message----- From: Kai Weber <weber@xxxxxxxxxxxxx> Sent: Fri, 11 May 2007 15:04:24 +0200 To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Subject: [xsl] Finding the path to a node Hello, First I would like to thank this list. So far all my problems with XSLT could be solved with your help. Thank you! I have a new one: I have to find the "root"-node of a node (not the document root, but a certain root). Let's say I want to find the root-page-node for page-node with id 4. Result should be page-node with id 1. A list of nodes 1,2,3 is acceptable, too. <pages> <page id="1"> <page id="2"> <page id="3"> <page id="4"> </page> </page> </page> </page> <page id="5" /> <page id="6" /> </pages> I tried with, but this is a loop and wrong... <xsl:apply-templates select="//page[@id='4']/ancestor:node()" /> Regards, Kai
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] Finding the path to a nod, Florent Georges | Thread | [xsl] various XSD format, Bru, Pierre |
Re: [xsl] various XSD format, Joe Fawcett | Date | RE: [xsl] various XSD format, Michael Kay |
Month |