[xsl] Extract input filename

Subject: [xsl] Extract input filename
From: "J. S. Rawat" <jrawat@xxxxxxxxxxxxxx>
Date: Thu, 17 May 2007 12:58:01 +0530
Dear Friends-
I have no idea about to extract input filename by passing argument in command line. In the below examples, I don't want to hardcode "input_meta.xml".


Input files
1. input.xml
2. input_meta.xml

command line
java -jar saxon8.jar input.xml x.xsl >c.xml

Stylesheet
<xsl:variable name="filename" select="document('input_meta.xml')" />
<xsl:template match="/">
	<doi>
      <xsl:copy-of select="$filename/doi/text()" />
	</doi>
</xsl:template>

Thanks in advance.
JSR

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