Subject: Re: [xsl] How do I change a XSL style sheet to group data together under one heading From: Abel Braaksma <abel.online@xxxxxxxxx> Date: Mon, 21 May 2007 10:35:42 +0200 |
Good day,
Thank you for your reply. I am aware of the one entry and have tried to run it with it as presented to you and without it with only sample_date_time. The result is the same. I receive the message for the following line:
<xsl:for-each select="sample[generate-id() = generate-id(key('sample',concat(sample_date_time, cp_name)[1])]">
line 15, Character 23 Stylesheet error: Invalid XPath expression select
Cheers, -- Abel
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