Re: [xsl] Sorting help

Subject: Re: [xsl] Sorting help
From: David Carlisle <davidc@xxxxxxxxx>
Date: Wed, 23 May 2007 15:25:42 +0100
<xsl:template match="@*" mode="copynode">

so when this template is activated the current node is an attribute (as
it matches @*)

            <xsl:copy>

copies the enitre attribute (including its value)

                        <xsl:apply-templates select="@*"
                        mode="copynode"/>

This will do nothing as attribute nodes never have attributes

                        <xsl:apply-templates mode="copynode"/>  

This will do nothing as attribute nodes never have child nodes.

            <xsl:for-each select="pd:Usage">
This will do nothing as attribute nodes can't have pd:Usage element children.
            <xsl:sort select="@UsagePurpose" order="descending" data-type="text"/>
                        </xsl:for-each>
            </xsl:copy>
</xsl:template>


I suspect that you want to move all of this code into the template that
matches eleemnts, but I couldn't tell from your descriptiuon what you
actually wanted to sort. (It woud lbe better to cut your example input
down to just 10 or so lines ((but still a well formed example) and then
show the desired output)

David

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