Subject: [xsl] call-template error From: Vaduvoiu Tiberiu <vaduvoiutibi@xxxxxxxxx> Date: Mon, 28 May 2007 03:24:13 -0700 (PDT) |
On my site I have a couple of categories/menus. Each time you're in a category it loads a different template(content) I have a parameter $menu which has the value of the name of the menu you are at on the site. So until now I had something like this: <xsl:if test="$menu= sport"> <xsl:call-template name="toolbox_sport"></xsl:call-template> </xsl:if> <xsl:if test="$menu= 'news"> <xsl:call-template name="toolbox_news"></xsl:call-template> </xsl:if> <xsl:if test="$menu= recent"> <xsl:call-template name="toolbox_recent"></xsl:call-template> </xsl:if> <xsl:if test="$menu= test"> <xsl:call-template name="toolbox_test"></xsl:call-template> </xsl:if> like this, it works. But then I though of making it more simple like this: <xsl:call-template name="toolbox_$menu"></xsl:call-template> so basically it should only loads the template of the selected menu. Thing is it doesn't work..I get java.util.EmptyStackException: I also tried creating a variable <xsl:variable name="tool">toolbox_<xsl:value-of select="$menu"/></xsl:variable> and then calling the template with the name="$tool"..also doesn't work. So why doesn't he load it?? 10x ____________________________________________________________________________________Take the Internet to Go: Yahoo!Go puts the Internet in your pocket: mail, news, photos & more. http://mobile.yahoo.com/go?refer=1GNXIC
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