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Subject: [xsl] following-sibling problem From: Andy Carr1 <CARRA@xxxxxxxxxx> Date: Wed, 6 Jun 2007 13:14:24 +0100 |
I have some source xml that looks like this:
<References>
<Reference>Something</Reference>
<Reference>Something Else</Reference>
<ReferenceReasonText>Reason for Something
Else</ReferenceReasonText>
<Reference>Another reference</Reference>
<References>
I'm applying a template match on References
<xsl:apply-templates select="References" />
and
<xsl:template match="References/Reference">
<!-- I've set up a test variable to determine if the
following-sibling is a <ReferenceReasonText> -->
<xsl:variable name="test">
<xsl:choose>
<xsl:when
test="following-sibling::ReferenceReasonText[1]">
<xsl:text>True</xsl:text>
</xsl:when>
<xsl:otherwise>
<xsl:text>False</xsl:text>
</xsl:otherwise>
</xsl:choose>
</xsl:variable>
</xsl:template>
The value of the test variable returns the following after transformation:
<References>
<Reference>Something</Reference> VARIABLE = TRUE
<Reference>Something Else</Reference> VARIABLE = TRUE
<ReferenceReasonText>Reason for Something
Else</ReferenceReasonText>
<Reference>Another reference</Reference> VARIABLE = FALSE
<References>
For the first instance of Reference I would expect the variable to be
False, what am I doing wrong ... anyone?
I've used following-sibling::xxxxx[1] before and got the results I
expected. The only difference that I can see is that this XSLT (v2.0) is
wrapped up in some FO using XEP 4.3 to produce PDF.
Regards
Andy
Andy Carr
Senior IT Specialist
Tel: Internal - 298037 External - 01252 558037
Mail Point M1C IBM Application Services
Meudon House, Meudon Avenue, Farnborough, GU14 7NB
(Notes) Andy Carr1/UK/IBM@IBMGB
(Internet)CARRA@xxxxxxxxxx
Unless stated otherwise above:
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