Re: [xsl] Getting a list of node Text()

[Nicholas Orr <nick@xxxxxxxxxxx>]

On 20/06/2007, at 8:51 AM, Houghton,Andrew wrote:

> > -----Original Message-----
> > From: Nicholas Orr [mailto:nick@xxxxxxxxxxx]
> >
> > Essentially I'm trying to get a <Calculation> node which will
> > be a child node of the current one.  But the issue is that
> > there will sometimes be one calculation node, and sometimes
> > multiple nodes.  And
> > they're not always just child nodes, they might be sub child nodes.
> > So I might have for my path :
> >
> > ./Calculation
> >
> > or
> >
> > ./Value/Calculation
> > ./StartPosition/Calculation
>
> I think you are over thinking the problem.  If all you want is the
> text from all the elements named Calculation then you should be
> able to do:
>
> ./descendant-or-self::Calculation/text()

Thanks, but in my testing this only returns the first Calculation  
node, not all of them.  I need all of them in a return separated list...

Thanks,
Nick