Re: [xsl] Sorting Using A Predefined Order

Subject: Re: [xsl] Sorting Using A Predefined Order
From: Jeff Sese <jsese@xxxxxxxxxxxx>
Date: Fri, 22 Jun 2007 10:27:49 +0800
Thanks for all the answers, I think I'll gonna go with Mr. Kay's solution cause the defined ordering lists a large number of keys.

-- Jeff

David Carlisle wrote:
Andrew> which can also be written as:

Andrew> <xsl:apply-templates select="(div[2], div[3], div[5], div[1], div[4])"/>


oh yes if we're using xpath2 there's other ways as well eg


<xsl:apply-templates select="for $p in (2,3,5,1,4) return div[$p]"/>


this is equivalent to Andrew's although actually neither's quite
equivalent to my original suggestion of 5 apply-templates calls, as in that case position() and last() would be equal to 1 each time
whereas in either of the versions here, last() is 5 and position() would
be 1..5, which is often preferable.


David

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