Re: [xsl] Replacing default namespace

[Martin Honnen <Martin.Honnen@xxxxxx>]

Abel Braaksma wrote:
> Martin Honnen wrote:
> > To avoid that use a template like this
> >
> >   <xsl:template match="*">
> >     <xsl:element name="{name()}" namespace="{namespace-uri()}">
> >       <xsl:apply-templates select="@* | node()"/>
> >     </xsl:element>
> >   </xsl:template>
> >
> > for element nodes that you want to copy without its namespaces nodes.
>
> Your code mimics the xsl:copy behavior. I assume you meant:
>
> <xsl:element name="{name()}" namespace="http://othernamespace";>

No, the original stylesheet had some templates for certain elements, for 
instance the root element of the original input document. For other 
elements it had the identity transformation template leading to elements 
like

>     <xs:simpleType xmlns:tns="http://tempuri.org/"; name="addrFormat">
>     <service xmlns:tns="http://tempuri.org/"; name="SessionsService"> 

in the result document as the xmlns:tns declarations were in scope from 
the root element of the input document. And the original poster wanted 
to get rid of the xmlns:tns on the elements above. That can be achieved 
by replacing the identity transformation template in the original 
stylesheet with my suggestion.


--

	Martin Honnen
	http://JavaScript.FAQTs.com/