RE: [xsl] comparing a part of the XML tree

[Owen Rees <owen.rees@xxxxxx>]

--On 15 July 2007 18:15 +0100 Michael Kay wrote:

> Calling deep-equal on every element would do the trick. It could
> potentially be quite expensive, but with luck deep-equal doesn't take
> very long when the arguments are obviously not equal, for example when
> they are elements with different names.

For the example given, deep-equal would not find any pair of items that 
match. The 'selection' element has two children but does not itself appear 
in the 'original' so there is no item in the selection that can be 
deep-equal to any item in the 'original'.

The first child of 'selection' does seem to be deep-equal to an item in 
'original' but the 'selection' item's following sibling - a text node - is 
not equal to the following sibling of the item in the 'original'. If spaces 
were to be normalised then the content of the 'selection' text node would 
be a prefix of the content of the 'original' text node.

--
Owen Rees
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