Re: [xsl] XPath for the selected node

["Dimitre Novatchev" <dnovatchev@xxxxxxxxx>]

http://www.topxml.com/code/default.asp?p=3&id=v20010323001030



--
Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without significant intelligence.
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To invent, you need a good imagination and a pile of junk
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You've achieved success in your field when you don't know whether what
you're doing is work or play




On 7/18/07, v vijith <vvijith@xxxxxxxxx> wrote:
> Dear All,
> I have an XML which has the structure like
>
> <root>
>     <data>
>          <node1>Welcome </node1>
>          <node2 refid="22">Some data</node2>
>      </data>
>      <anotherdata>
>               <sometype refid=33>welcome</sometype>
>       </anotherdata>
> </root>
>
> Using Xquery is there a way to find the xpath of all the nodes that
> has refid as an attribute? For the above case, the answer that I would
> be looking at it
>
> root/data/node2
> root/anotherdata/sometype
>
> I went through some of the posts and found that saxon:path is an
> option. Do I have any other way of doing it?
>
> Any kind of pointer is appreciated!!
>
> Thanks
> Vij