Subject: RE: [xsl] Select the nearest of two preceding siblings From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Fri, 20 Jul 2007 10:20:50 +0100 |
> Sorry if this is too simple, but I'm still a bit new at this. > I need to compare the relative positions of two preceding > siblings and grab the value of the nearest one. I haven't managed to follow the detail of your requirement, but given two nodes $A and $B you can select the one that comes last in document order using ($A|$B)[last()] or if you prefer if ($A>>$B) then $A else $B Michael Kay http://www.saxonica.com/
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