Re: [xsl] Finding the current node type

[David Carlisle <davidc@xxxxxxxxx>]

you don't mean node type which means (in xpath parlance)  "element" or
"comment" etc. You want the node name test, along the self axis rather
than the default child axis, so

		<xsl:when test="self::speaker">

note however that dowing a big xsl:choose matching on node names is just
a poor man's version of template matching. If there are only two cases
it doesn't really matter but it's usually more efficient to use template
matching as the system will (probably) have some efficient hashed switch
on element names, but an xsl:choose probably implies a sequential set of
tests so time proportional to the number of cases.

so you could code it as

<xsl:apply-templates match="speaker|laptop"/>


<xsl:template match="speaker">
	<!-- Assign a sequential Number -->
	Item No: <xsl:value-of select="position()"/> <br />
	<!-- Now output item-specific details -->
			RMS Power: <xsl:value-of select="rms_power"/>
<br />
			Peak Power: <xsl:value-of select="peak_power"/>
<br />	
...

David


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