Subject: Re: [xsl] Finding the current node type From: Abel Braaksma <abel.online@xxxxxxxxx> Date: Wed, 01 Aug 2007 16:13:42 +0200 |
Thanks Guys
In my application, I will only need to process a few hundred nodes and
about 20-30 of the type where I need to use the choose statement.
I went with the <xsl:if test=self::speaker> option as I still use the
namespace (e.g. <xsl:if test=self::abc:speaker>). Whereas localname
returned the node name without the ns prefix
Cheers, -- Abel Braaksma
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