Subject: [xsl] using contains() to search xml doc and matching regardless of case From: "Jessica Hennessey" <jessica@xxxxxxxxxxxxxxxxxxxxxxx> Date: Thu, 2 Aug 2007 23:14:40 -0400 |
I am trying to filter my xml document to only output records based on a search string. I have the basic search functionality working using the xsl:if and the contains() function. Unfortunately for me, this is searching for an exact match including case. I need it to be case insensitive. My initial thought was to make everything in my search field lowercase and force my incoming parameter to be lowercase. However, I couldn't seem to do that from within the contains function. The publicdescription field is not displayed on this page, so I can do anything I want to it. Here is my xsl <?xml version='1.0'?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:param name="order"/> <xsl:param name="orderdirection"/> <xsl:param name="filter"/> <xsl:template match="/"> <xsl:for-each select="root/job"> <xsl:sort select="*[name()=$order]" order="{$orderdirection}"/> <xsl:if test="contains(PUBLICDESCRIPTION_STRING, $filter)"> <tr> <td><a> <xsl:attribute name="href">jobdetail.asp?jobid=<xsl:value-of select="JOBPOSTINGID_INT"/></xsl:attribute> <xsl:value-of select="TITLE_STRING" /></a></td> <td><xsl:value-of select="CITY_STRING"/>, <xsl:value-of select="STATE_STRING"/></td> <td><xsl:value-of select="EMPLOYMENTTYPE_STRING"/></td> </tr> </xsl:if> </xsl:for-each> </xsl:template> </xsl:stylesheet> Thanks to everyone who got me this far!!!I think this is the last obstacle. Jessica Hennessey Sunlight Studios - Internet Consulting & Development www.sunlightstudios-icd.com
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