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Re: [xsl] Re: Format Number and Empy Elements

Subject: Re: [xsl] Re: Format Number and Empy Elements
From: Florent Georges <darkman_spam@xxxxxxxx>
Date: Wed, 8 Aug 2007 18:46:38 +0200 (CEST)
Mark Anderson wrote:

  Hi

> Strangely, sum(value[.]) still gave NaN for Element A

  The predicate [.] will always be true, as an existing node is
converted to true (meaning "yes, I exist").  This is not the same for
[string(.)] however.

  Regards,

--drkm























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