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Subject: [xsl] While copying everything, append attribute value with incremental index. From: Xuan Ngo <xuanngo2001@xxxxxxxxx> Date: Fri, 10 Aug 2007 20:27:58 -0700 (PDT) |
I would like to append the value of the attribute "p" with an incremental index using position()
function but position() is only giving me 1s.
Input:
========
<?xml version="1.0" encoding="UTF-8"?>
<root>
<M i="k">1</M>
<A i="p"><B><C>5</C></B></A>
<A i="p"><B><C>5</C></B></A>
<A i="p"><B><C>5</C></B></A>
</root>
What I want:
=============
<?xml version="1.0" encoding="UTF-8"?>
<root>
<M i="k">1</M>
<A i="p_1"><B><C>5</C></B></A>
<A i="p_2"><B><C>5</C></B></A>
<A i="p_3"><B><C>5</C></B></A>
</root>
Output From the XSL:
=====================
<?xml version="1.0" encoding="UTF-8"?>
<root>
<M i="k">1</M>
<A i="p_1"><B><C>5</C></B></A>
<A i="p_1"><B><C>5</C></B></A>
<A i="p_1"><B><C>5</C></B></A>
</root>
XSL:
======
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:fo="http://www.w3.org/1999/XSL/Format">
<xsl:output method="xml" encoding="UTF-8" />
<!-- Copy everything -->
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()">
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
<xsl:template match="@i[parent::A]">
<xsl:attribute name="i"><xsl:value-of select="concat(., '_')"/><xsl:value-of
select="position()"/></xsl:attribute>
</xsl:template>
</xsl:stylesheet>
thx!
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