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[xsl] xsl:choose and xsl:when

Subject: [xsl] xsl:choose and xsl:when
From: oryann9 <oryann9@xxxxxxxxx>
Date: Tue, 28 Aug 2007 15:43:43 -0700 (PDT)
Hello all, 

Still new to xsl and xml, but I am getting stuck on
one of my online class lessons from oreilly. I need to
use another xsl:when to output (HOME) when the TYPE
attribute is empty.

Here is what I have thus far:
Was not sure what it means to be empty in xsl, but I
have used <xsl:when test="(PHONE/@TYPE='')"> and other
similar trys with no luck.

please help
thx!

__CODE__

<?xml version="1.0" ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="html"/>
<xsl:template match="/">
     <HTML>
     <HEAD>
     <TITLE>My Phone Book</TITLE>
     </HEAD>
     <BODY BGCOLOR="BLACK">
          <xsl:apply-templates select="//LISTING" />
     </BODY>
     </HTML>
</xsl:template>
<xsl:template match="LISTING">
     <FONT COLOR="WHITE"><xsl:value-of
select="LAST"/>,
          <xsl:value-of select="FIRST"/></FONT>
     <FONT COLOR="orange" SIZE="+2"><xsl:value-of
select="PHONE"/>
<xsl:choose>
      <xsl:when test="boolean(PHONE/@TYPE)">
           (<xsl:value-of select="PHONE/@TYPE" />)
      </xsl:when>
       <xsl:when test="(PHONE/@TYPE='')">
            (HOME)
      </xsl:when>
      <xsl:otherwise>
           (HOME)
      </xsl:otherwise>
</xsl:choose>
     </FONT>
</xsl:template>
</xsl:stylesheet>


       
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