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Subject: Re: [xsl] Identical entries in different input documents   should appear in the output document only once From: David Carlisle <davidc@xxxxxxxxx> Date: Fri, 7 Sep 2007 21:54:34 +0100  | 
> That's all ... Wow :-)
it's a bit more than you need though:-)
   <xsl:for-each select="current-group()[1]"> <!-- In my case all blocks
is (always) the same thing as
   <xsl:for-each select="."> <!-- In my case all blocks
which is always the same thing as
     <!-- In my case all blocks
so the code can be
<xsl:for-each-group select="document($allFiles)//root/block"
group-by="idTag">
 <!-- In my case all blocks
from different files are really identical -->
      <xsl:call-template name="makeMyTransformationOnTheBlock"/>
</xsl:for-each-group>
If <root> is always the top level element, using /root/block instead of
//root/block would save the processor a lot of work as // implies
(except when Michael optimizes it away) a full search to arbitrary depth
of each document to find all elements of that name.
David
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