Re: [xsl] XSL: Format date

Subject: Re: [xsl] XSL: Format date
From: Abel Braaksma <>
Date: Sat, 29 Sep 2007 00:28:46 +0200
Hi HC,

I hope you are using XSLT 2.0 (you didn't specify), though it wouldn't be hard in XSLT 1.0, it is just so much easier 2.0. Here it goes:

<xsl:sequence select="replace(first/date, '(\d+)\.(\d+)\.(\d+)', '\2/\1/\3') />

hmm, while writing it, looks pretty obfuscated hehe. Perhaps the XSLT 1.0 way with nested substring-before is clearer after all. An alternative approach would be to convert it into a date and use format-date() on it.

Thinking of Larry Wall's: there's more than one way to do it. Though XSLT is not Perl, it can get close. Here's another method (and I'm sure there're a thousand more!):

<xsl:value-of select="for $i in (2,1,3) return tokenize(first/date, '\.')[$i]" separator="/" />

if you need some extra explanation on these ones, I am happy to help you further. Btw, I personally like that last solution, just happened to come up like that ;)

-- Abel Braaksma

Chaudhary, Harsh wrote:

I am sure this has been discussed to death but I have not been able to
find a good source of info on it.

I have an xml:


I would like to convert it to 12/31/2006.

Is there any built in function for this or is string formatting the way
to go?


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