Subject: RE: [xsl] position() outside for-each From: "Scott Trenda" <Scott.Trenda@xxxxxxxx> Date: Tue, 13 Nov 2007 16:57:14 -0600 |
What position are you trying to determine, exactly? Do you have any sorting applied when you apply-templates to /root/item? Are you trying to determine the position of the node within its parent node, the position of the node within the document, the position of the node within the context node-set...? There's lots of different ways you can ask for the position of a node, but the position() function will follow a very specific algorithm every time. You can retrieve a variety of different results with the <xsl:number/> element: <xsl:template match="/root/item"> <xsl:number level="single" count="item" format="1:"/> <xsl:value-of select="@id"/> </xsl:template> ~ Scott -----Original Message----- From: Charles Ohana [mailto:charles.ohana@xxxxxxxxxxxxxx] Sent: Tuesday, November 13, 2007 4:39 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] position() outside for-each Hello, I'm trying to determine the position of a node, the issue is that it's within a for-each loop. See snippet below to see what I'm trying to accomplish. Thanx <root> <item id="XYZ" /> <item id="A23" /> <item id="z49" /> <item id="X12" /> </root> <xsl:template match="/root/item"> <xsl:value-of select="position()" /> <xsl:text>:</xsl:text> <xsl:value-of select="@id" /> </xsl:template>
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