Subject: RE: [xsl] get value from link from last slash From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Wed, 14 Nov 2007 08:32:07 -0000 |
In 1.0 you need a recursive template to do this. The logic is template name="last-part" if contains($in, '/') then call-template last-part (with-param $in = substring-after($in, '/')) else $in Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Vaduvoiu Tiberiu [mailto:vaduvoiutibi@xxxxxxxxx] > Sent: 14 November 2007 07:56 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] get value from link from last slash > > Hi, I have a little wierd problem. i have an xml where I have > a bunch of image links like: > > root/statics/images/image.jpg > root/images2/image2.jpg > > is there a way to extract the names of the images using xslt > 1.0? I need to extract the names of the images...image.jpg, > image2.jp, etc. I thought about using substring but there are > more than a slash in the path. Basically I would need the > string from the last slash to the end. Sounds a little > complicated but is there a way around it? 10x > > > > > > ______________________________________________________________ > ______________________ > Get easy, one-click access to your favorites. > Make Yahoo! your homepage. > http://www.yahoo.com/r/hs
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