Re: [xsl] xsl:for-each-group Problem

["Andrew Welch" <andrew.j.welch@xxxxxxxxx>]

On 21/11/2007, Byomokesh Sahoo <sahoo.byomokesh@xxxxxxxxx> wrote:
> Hi All,
>
> I am facing xsl-for-each group problem in my Input xml file. Please
> see below my Input file.
>
> XML File
> ========
>
> <researcher>
> <title>Rethinking Foreign Policy</title>
> <question>Approach be abandoned?</question>
> <abstract>some Text</abstract>
> <section>Section The Issues</section>
> <para>some text</para>
> <section>Background</section>
> <para>some text</para>
> </researcher>
>
> I need ouput
> ============
>
> <researcher>
> <cover>
> <title>Rethinking Foreign Policy</title>
> <question>Approach be abandoned?</question>
> <abstract>some Text</abstract>
> </cover>
> <section label="the.issues">
> <section>Section The Issues</section>
> <para>some text</para>
> </section>
> <section label="Background">
> <section>Background</section>
> <para>some text</para>
> </section>
> </researcher>

Use:

    <xsl:template match="researcher">
        <xsl:for-each-group select="*" group-starting-with="section">
            <xsl:choose>
                <xsl:when test="current-group()[1][self::title]">
                    <cover>
                        <xsl:copy-of select="current-group()"/>
                    </cover>
                </xsl:when>
                <xsl:otherwise>
                    <section label="{.[self::section]}">
                        <xsl:copy-of select="current-group()"/>
                    </section>
                </xsl:otherwise>
            </xsl:choose>
        </xsl:for-each-group>
    </xsl:template>

You'll need to sort out the label attribute to be how you want it, as
its not obvious from your example output.


cheers
-- 
Andrew Welch
http://andrewjwelch.com
Kernow: http://kernowforsaxon.sf.net/