Subject: Re: [xsl] XSLT 1.0 and XSLT 2.0 differences in position()? From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 13 Dec 2007 01:58:58 GMT |
<xsl:if test="position( ) !=last( )">, </xsl:if> <xsl:if test="position( )=last()-1">and </xsl:if> If you are processing every item then clearly (if there are more 1 items) this will make ", and" as on the last but one iteration position()!=last(0 so you get a , and it is equal to last()-1 so you get and as well. If you only want , in the cases before you do and, not overlapping cases, then code it that way: <xsl:if test="position( ) < last( )-1">, </xsl:if> <xsl:if test="position( )=last()-1">and </xsl:if> the difference between xslt 1 and 2 is that in xslt 1 you are probably just processing the items in positions 2,4,6,... with intervening items being white space, that;s a dangerous practice (if you have any white space after the last item the "and" will come in the wrong place. xslt 2 (if you have a suitable dtd/schema) will autmatically throw away the white space. If you are using position() it's safest to explictly make sure just the right nodes are select by going for example apply-templates select="xyz"/. rather than <xsl:apply-templates/. David ________________________________________________________________________ The Numerical Algorithms Group Ltd is a company registered in England and Wales with company number 1249803. The registered office is: Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom. This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. ________________________________________________________________________
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