RE: [xsl] problem with xsl:if test statement

Subject: RE: [xsl] problem with xsl:if test statement
From: "John Horner" <Horner.John@xxxxxxxxxx>
Date: Tue, 18 Dec 2007 17:14:38 +1100
I'm rather confused by this question/example code.

Given the code you've sent us, it *doesn't* produce two links. The
for-each works once for each Fruits node, and if it matches the country
and the fruit, produces one link, even if there are two
<Type>Apples</Type> nodes.

Perhaps the answer to the more general question is to use count()? As

	<xsl:for-each select="Products">
		<xsl:if test="count(Fruits[Type='Apples']) &gt; 0 ">
		there is at least one 'Apples' node in the
		Product node for <xsl:value-of select="Fruits/Country"/>

By the way, there are quite a few mistakes in your code and it doesn't
run without fixing them. I suspect you didn't send us the code you're
actually working on?

-----Original Message-----
From: Amy Huang [mailto:h.amy88@xxxxxxxxx]
Sent: Tuesday, 18 December 2007 3:51 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] problem with xsl:if test statement


I'm new to xml and xsl. I need to generate one link if my query finds
one or more records in my XML document. But I if I use "for each
statement", the link will repeat again and again depending on how many
records satisfy my query. E.g., if 2 records satisfy my query, the link
will repeat twice like this:

For apples, click here
For apples, click here

How can I generate only one link if my query finds more than one

<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet version="1.0"

<xsl:param name="Country" select="Mexico" ></xsl:param>
<xsl:template match="/">
<h2>Types of Fruits</h2>
<xsl:for-each select="Products/Fruits">
<xsl:if test="Country = $Country and Type = 'Apples'">
<xsl:attribute name="href">
fruits.aspx?moi=<xsl:value-of select="$Country"/>
For apples, click here
<br />


Any help would be greatly appreciated!

Amy Huang

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