Subject: Re: [xsl] xalan and replace "regex" From: Mansour <mansour77@xxxxxxxxx> Date: Thu, 27 Dec 2007 10:09:48 -0400 |
Is there any way I can use replace with xalan.
The replace() function is new in XSLT 2.0, and Xalan only supports XSLT 1.0. Switch to Saxon.
Michael Kay http://www.saxonica.com/
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