Subject: Re: [xsl] xalan and replace "regex" From: Mansour <mansour77@xxxxxxxxx> Date: Thu, 27 Dec 2007 20:18:00 -0400 |
<xsl:template match="program"> <xsl:call-template name="str:replace"> <xsl:with-param name="string" select="." /> <xsl:with-param name="search" select="public" /> <xsl:with-param name="replace" select="object" /> </xsl:call-template> </xsl:template>
Matthew L. Avizinis wrote:
also check out: http://xml.apache.org/xalan-j/extensionslib.html#exslt http://www.exslt.org for examples
Mansour wrote:
Hello: Is there any way I can use replace with xalan. I have tried every thing possible but couldn't get it to work:
<?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xalan="http://xml.apache.org/xalan" xmlns:str="http://exslt.org/strings"> <xsl:import href="str/str.xsl" /> <xsl:template match="program"> <xsl:value-of select="replace(.,'public','<KeyWord> pulic </KeyWord>')" /> </xsl:template> </xsl:stylesheet>
I need to scan a piece of java code and be able to highlight the words based on their meaning. Anyone had luck with xalan regex ?? or analyze-string ??
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