Subject: Re: [xsl] Help with XPath statement From: Florent Georges <lists@xxxxxxxxxxxx> Date: Mon, 3 Mar 2008 00:35:32 +0100 (CET) |
Raymond Bissonnette wrote: > I'm stuck with XSLT 1.0 (ASP.NET) and worse, what I'm after is > to get a list of <set ... > nodes with the SelectNodes method > of an XmlDocument. I don't know XmlDocument. If you want XSLT, change <xsl:value-of select="."/> by <xsl:copy-of select=".."/> in the solution Ken proposed to you. If you want an XPath: section[@id = '0802']/set[ not(@key = ../following-sibling::section/set/@key) ] | section[@id = '0803']/set or: section[@id = '0802']/set[ not(@key = ../../section[@id = '0803']/set/@key) ] | section[@id = '0803']/set should be what you are after. Not tested! Regards, --drkm _____________________________________________________________________________ Ne gardez plus qu'une seule adresse mail ! Copiez vos mails vers Yahoo! Mail http://mail.yahoo.fr
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