Re: [xsl] [XSLT] Put element in new-line

[Florent Georges <lists@xxxxxxxxxxxx>]

Michael Ludwig wrote:

  Hi

>    <xsl:output indent="yes"/>
>    <xsl:template match="/">
>      <xsl:apply-templates select="node() | @*"/>
>    </xsl:template>
>    <xsl:template match="node() | @*">
>      <xsl:copy>
>        <xsl:apply-templates select="node() | @*"/>
>      </xsl:copy>
>    </xsl:template>

  The usual Identity Transform Pattern is:

    <xsl:template match="node()|@*">
       <xsl:copy>
          <xsl:apply-templates select="node()|@*"/>
       </xsl:copy>
    </xsl:template>

  Adding the rule for the document node won't change anything (well,
except if your serializer behaves differently whether it gets a
document or an element node, what is unlikely, especially if you use
xsl:output.)

  Regards,

--drkm
























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