Re: [xsl] Count preceding cousins and siblings

[Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>]

Jim,

At 04:28 PM 3/12/2008, you wrote:
> I need to be able to count the preceding cousins and siblings.

In 2.0, count(../../*/*[. << current()]) (assuming you want 
only elements)

or count(../../*/* intersect preceding::*)

Someone more knowledgeable about inner workings will have to suggest 
which is likely to be more efficient. I suspect the first one.

> Thanks to Wendell for a quick correct solution to the adding hierarchy
> problem. I spent three days on it without success.

You're welcome. One is always nervous sending untested code out into 
the ether -- although mind you, the algorithm was tested (I have 
faced that problem in the past).

Cheers,
Wendell


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Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc.                http://www.mulberrytech.com
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