Subject: [xsl] Selecting unparsed text from inside a tag From: "Jefferson Thomas" <foramuyou@xxxxxxxxx> Date: Tue, 25 Mar 2008 17:58:21 +0900 |
Hi, I would like to know if there is a way to select everything that is inside a tag without parsing it and put it to the output, so that if there are other tags (like <br/> or <html>) inside our tag then they will also come up. Here is an example: xml: <?xml version="1.0" encoding="utf-8"?> <?xml-stylesheet type="text/xsl" href="test.xsl"?> <test> TEST<br/><img src="test.jpg" /> </test> xsl: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:template match="/test"> <html> <body> <xsl:value-of select="."/> </body> </html> </xsl:template> </xsl:stylesheet> output that comes out: <html> <body>TEST</body> </html> output that I want: <html> <body>TEST<br/><img src="test.jpg" /></body> </html> So the difference is that the <br/> and <img> would also come up. As for now I couldnt find any way for that. Does somebody know how to do it ? Thanks for any help, Thomas
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