Subject: RE: [xsl] Splitting files 5 at a time From: "Houghton,Andrew" <houghtoa@xxxxxxxx> Date: Wed, 2 Apr 2008 14:49:31 -0400 |
> From: David Carlisle [mailto:davidc@xxxxxxxxx] > Sent: 02 April, 2008 14:37 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Re: [xsl] Splitting files 5 at a time > > > > [count() mod 5 = 0] > > [position() mod 5 = 1] I thought I understood his problem to be that he wanted the first five customers in one file, then the next five customers in the next, etc. If he just did what you suggested wouldn't he just grab every 1 in 5 customers out of the group of five customers? Customer 1 => position() mod 5 = 1 Customer 2 => position() mod 5 = 2 Customer 3 => position() mod 5 = 3 Customer 4 => position() mod 5 = 4 Customer 5 => position() mod 5 = 0 Customer 6 => position() mod 5 = 1 Customer 7 => position() mod 5 = 2 Customer 8 => position() mod 5 = 3 Customer 9 => position() mod 5 = 4 Customer 10 => position() mod 5 = 0 So if I understood your solution, he would create the first file with Customer 1, 6, 11, 16, 21 and not Customer 1, 2, 3, 4, 5. Is that correct? Andy.
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